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so S = 2E22m<sup>2</sup>
so S = 2E22m<sup>2</sup>


and if each mirror is 1E6<sup>2</sup> then a full swarm has 2E16 mirrors which is 20 quadrillion mirrors. If they are overlapping circles then there's 30 quadrillion.
and if each mirror = 1E6<sup>2</sup> then a full swarm has 2E16 mirrors which is 20 quadrillion mirrors. If they are overlapping circles then there's 30 quadrillion.


A 1% swarm at an orbit of 40 million km is 2E14 mirrors. 200 trillion mirrors.
A 1% swarm at an orbit of 40 million km = 2E14 mirrors = 200 trillion mirrors.


Ten years is 3.1536E8 seconds which is 634 mirrors a second. Nearly all of those are in the final year.
Ten years is 3.1536E8 seconds which is 634 mirrors a second. Nearly all of those are in the final year.

Revision as of 19:29, 5 January 2020

A mirror orbits the sun and reflects light to a receiver.

It has neighbours. They are close enough to message each other. They are an internet.

They all have the same distance from the sun.

A full swarm catching all the light of the sun would have an area of S = 4πr2

r=4E10m

so S = 2E22m2

and if each mirror = 1E62 then a full swarm has 2E16 mirrors which is 20 quadrillion mirrors. If they are overlapping circles then there's 30 quadrillion.

A 1% swarm at an orbit of 40 million km = 2E14 mirrors = 200 trillion mirrors.

Ten years is 3.1536E8 seconds which is 634 mirrors a second. Nearly all of those are in the final year.

Before the final year a single railgun is enough with 30 launches a second to escape velocity. The mirror will then tack to its right position.

The orbit distance of a mirror around the sun is 2πr = 2.5E11m

Solar orbit period = 70 days, speed in solar orbit = 41km/s

Escape velocity of Mercury = 4.3km/s